(y-3)*(y+2)=(y^2-1)

Solution for (y-3)*(y+2)=(y^2-1) equation:

Simplifying
(y + -3)(y + 2) = (y2 + -1)

Reorder the terms:
(-3 + y)(y + 2) = (y2 + -1)

Reorder the terms:
(-3 + y)(2 + y) = (y2 + -1)

Multiply (-3 + y) * (2 + y)
(-3(2 + y) + y(2 + y)) = (y2 + -1)
((2 * -3 + y * -3) + y(2 + y)) = (y2 + -1)
((-6 + -3y) + y(2 + y)) = (y2 + -1)
(-6 + -3y + (2 * y + y * y)) = (y2 + -1)
(-6 + -3y + (2y + y2)) = (y2 + -1)

Combine like terms: -3y + 2y = -1y
(-6 + -1y + y2) = (y2 + -1)

Reorder the terms:
-6 + -1y + y2 = (-1 + y2)

Remove parenthesis around (-1 + y2)
-6 + -1y + y2 = -1 + y2

Add '-1y2' to each side of the equation.
-6 + -1y + y2 + -1y2 = -1 + y2 + -1y2

Combine like terms: y2 + -1y2 = 0
-6 + -1y + 0 = -1 + y2 + -1y2
-6 + -1y = -1 + y2 + -1y2

Combine like terms: y2 + -1y2 = 0
-6 + -1y = -1 + 0
-6 + -1y = -1

Solving
-6 + -1y = -1

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + -1y = -1 + 6

Combine like terms: -6 + 6 = 0
0 + -1y = -1 + 6
-1y = -1 + 6

Combine like terms: -1 + 6 = 5
-1y = 5

Divide each side by '-1'.
y = -5

Simplifying
y = -5